ষষ্ঠ শ্রেনী থেকে দশম শ্রেণী পর্যন্ত সকল বীজগানিতিক সূত্র
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➲ (a + b)2 = a2 + 2ab + b2
➲ (a + b)2 = (a
– b)2 + 4ab
➲ (a – b)2 = a2
– 2ab + b2
➲ (a – b)2 = (a
+ b)2 – 4ab
➲ a2 + b2
= (a + b)2 – 2ab
➲ a2 + b2
= (a – b)2 + 2ab
➲ a2 – b2
= (a + b) – (a – b)
➲ 2(a2+b2)
= (a + b)2 + (a – b)2
➲ (a + b + c)2 =
(a2 + b2 + c2) + 2(ab + bc + ca)
➲ (a2 + b2
+ c2) = (a + b + c)2 – 2(ab + bc + ca)
➲ 2(ab + bc + ca) = (a + b +
c)2 – (a2 + b2 + c2)
➲ (a + b)3 = a3
+ 3a2b + 3ab2 + b3
➲ (a + b)3 = a3
+ b3 + 3ab(a + b)
➲ (a – b)3 = a3
– 3a2b + 3ab2 – b3
➲ (a – b)3= a3
– b3– 3ab(a – b)
➲a3 + b3=
(a + b)( a2 – ab + b2)
➲a3 + b3
= (a + b)3 – 3ab(a + b)
➲a3 – b3=
(a – b)( a2 +ab + b2)
➲a3 – b3=
(a – b)3 + 3ab(a – b)
➲ (a + b + c)3 =
a3 + b3 + c3 + 3(a + b) (b + c) (c + a)
➲ a3 + b3
+ c3 – 3abc = (a + b + c) (a2 + b2+ c2
– ab – bc – ca)
➲ a3 + b3
+ c3 – 3abc = (a + b + c) { (a – b)2 + (b – c)2
+ (c – a)2 }
➲ (x + a) (x + b) = x2
+ (a + b) x + ab
➲ (x + a) (x – b) = x2
+ (a – b) x – ab
➲ (x – a) (x + b) = x2
+ (b – a) x – ab
➲ (x – a) (x – b) = x2
– (a + b) x + ab
➲ (x + p) (x + q) (x + r) =
x3 + (p + q + r) x2 + (pq + qr + rp) x +pqr
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